Your answer will determine the ending.
At a surface level, it’s a survival-probability riddle. The long way is to track each shot. On shot one, the first guy has a 50% chance to live (3 of 6 chambers are empty). If he lives, the round must be in slot 1, 2, or 3. That makes the second guy safe only if it was in slot 1 or 2—so his survival chance is 2/3 (66.6%), and so on, to calculate the total probability. A quicker approach is to consider the total probability from the outset: for which first-shot positions does the second man die before the first?
Be honest… You’re such a chicken you grabbed a second hint just to boost your odds of staying alive. Sure, it may be a probability puzzle, but it’s also a challenge of bravery, a riddle about courage and facing the fear of death. This is the last hint I’ll give you: answer with the strength of your soul.
The “right” answer depends on the motive behind the decision. Thinking in cold logic, whoever chooses to go first has lower chances of survival. In fact, the one who goes second will die before the first one only if the first shot lands in positions 1 or 3 (2/6, i.e., 33.3%).
